replace trailing whitespace with blackslash in README.md
As an alternative to the markdown trailing whitespace as a line break, we use a trailing blackslash as a markdown line break.
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@@ -1,6 +1,6 @@
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# Best Output
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Carlos Duarte
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Carlos Duarte\
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Portugal
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@@ -1,9 +1,9 @@
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# Most Humorous
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Don Dodson
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AG Communication Systems
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4101 W Union Hills Dr #1104
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Glendale, AZ 85308
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Don Dodson\
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AG Communication Systems\
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4101 W Union Hills Dr #1104\
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Glendale, AZ 85308\
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US
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## To build:
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@@ -1,6 +1,6 @@
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# Best Game
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Don Dodson
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Don Dodson\
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US
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## To build:
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@@ -1,8 +1,8 @@
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# Interesting Algorithm
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Sebastian Deorowicz
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ul. Radzionkowska 71a
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42-605 Tarnowskie Gory
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Sebastian Deorowicz\
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ul. Radzionkowska 71a\
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42-605 Tarnowskie Gory\
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Poland
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## To build:
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@@ -1,9 +1,9 @@
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# Best Layout
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Heather Downs & Selene Makarios
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The Software Bungalow
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900 High School Way, #2202
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Mountain View, CA 94041
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Heather Downs & Selene Makarios\
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The Software Bungalow\
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900 High School Way, #2202\
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Mountain View, CA 94041\
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US
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## To build:
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+7
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@@ -1,8 +1,8 @@
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# Best Use of Obfuscation
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Leonid A. Broukhis
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46728 Crawford St., apt. 20
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Fremont, CA 94539
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Leonid A. Broukhis\
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46728 Crawford St., apt. 20\
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Fremont, CA 94539\
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US
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## To build:
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@@ -167,7 +167,7 @@ Step 6:
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depending on the desired "hairiness". The original (paper-based)
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algorithm was "hairy", but it didn't look as good on the screen.
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\
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The program cannot handle non-hairy mode 100% correctly - step 6 happens
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to be
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@@ -190,7 +190,7 @@ the opening for step 1 is not a single line but a cross:
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```
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\./
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/ \
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\
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```
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To watch it repeatedly (as a screensaver), use:
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@@ -207,7 +207,7 @@ The command line:
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draws the same as above. Try:
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```sh
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```sh\
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./leo Variable 1 1 | cat - /dev/tty | gs -
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```
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@@ -224,7 +224,7 @@ if you want to pipe the output to a printer.
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begin 664 spoiler1
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M*%1H92!C;VQO;B J:7,J('1H92!S96-R970@<W=I=&-H("T@=&AE('-P86-E
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=(&)E9F]R92!I="!I<R!N;W0@82!M:7-T86ME*0II
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\
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end
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```
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@@ -1,9 +1,9 @@
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# Best Short Program
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Selene Makarios & Heather Downs
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The Software Bungalow
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900 High School Way, #2202
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Mountain View, CA 94041
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Selene Makarios & Heather Downs\
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The Software Bungalow\
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900 High School Way, #2202\
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Mountain View, CA 94041\
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US
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## To build:
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@@ -1,9 +1,9 @@
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# Most Obfuscated Syntax
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Michael Savastio
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Securicor Telesciences
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925 1/2 Anchor St, Apt 2
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Philadelphia, PA 19124
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Michael Savastio\
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Securicor Telesciences\
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925 1/2 Anchor St, Apt 2\
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Philadelphia, PA 19124\
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US
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## To build:
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@@ -1,10 +1,10 @@
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# Best One Liner
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Mark Schnitzius
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ISX Corporation
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3215-C Post Woods Dr.
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Atlanta, GA 30339
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US
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Mark Schnitzius\
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ISX Corporation\
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3215-C Post Woods Dr.\
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Atlanta, GA 30339\
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US\
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<http://computronium.org/ioccc.html>
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@@ -1,8 +1,8 @@
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# Abusing The Rules
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Diomidis Spinellis
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Greece
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<https://www.spinellis.gr/>
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Diomidis Spinellis\
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Greece\
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<https://www.spinellis.gr/>\
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Mastodon: <https://mstdn.social/@DSpinellis>
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## To build:
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@@ -1,10 +1,10 @@
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# Worst Abuse of the C Preprocessor and Most Likely To Amaze
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Mark Schnitzius & David Van Brackle
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ISX Corporation
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1165 Northchase Parkway
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Suite 120
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Marietta, GA 30067
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Mark Schnitzius & David Van Brackle\
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ISX Corporation\
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1165 Northchase Parkway\
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Suite 120\
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Marietta, GA 30067\
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US
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## To build:
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@@ -53,7 +53,7 @@ never be placed on top of a smaller disk.
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Our program solves the Towers of Hanoi problem. Well, that's
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not exactly true; actually, it's the compiler that solves the
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problem. The resulting program just prints out the correct
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problem. The resulting program just prints out the correct\
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solution.
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How do you trick a compiler into actually solving the problem?
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@@ -70,7 +70,7 @@ gcc hanoi.c -o hanoi -Dn=4
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A default value of `5` will be used for `n` if you do not define
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it on the command line. The value of `n` cannot be greater than
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fifteen (the compiler we used to test has a limit on the #include
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depth). The compiler then solves the problem using binary
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depth). The compiler then solves the problem using binary\
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arithmetic based on whether particular symbols are defined or not.
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To loop, the program `#include`s itself. This is, of course,
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@@ -97,7 +97,7 @@ gcc hanoi.c -E -Dn=5 | grep -v \# | grep -v ^\$
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For an odd number of disks, the program will provide a
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solution wherein the disks end up on peg 2; for an even
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number of disks, they will end on peg 3. This should
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number of disks, they will end on peg 3. This should\
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provide some hint as to what sort of algorithm is used.
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We have included a [spoiler](spoiler.c) version of the program, with
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