add hack-a-round for language specified markdown code blocks
When language is specified in a markdown code block such as:
````
```c
printf("Hello, world!\n");
```
````
is used, the resulting HTML as produced by `pandoc(1)` combined
with our revised `ioccc.css` is not intent the code block well.
A temporary "_hack-a-round_" is to turn the "markdown code language
specifier" into an HTML comment. For example:
````
```<!---c-->
printf("Hello, world!\n");
```
````
This commits turns off existing markdown code language specifiers
for now, while preserving our ability to restore them in the future
when a better "_hack-a-round_" to the "markdown code language
specifier" problem is found.
The HTML impact if this "_hack-a-round_" is to produce HTML that
looks like this:
```
<pre class="<!---c-->"><code> .. </code></pre>
```
We might be able to create a complex set of classes for each markdown
code language (there won't be very many) in `ioccc.css`, or we might
find a more general CSS (or maybe `pandoc(1)`?) solution.
For now, this hack-a-round will have to do.
This commit is contained in:
Landon Curt Noll committed
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@@ -1,13 +1,13 @@
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## To build:
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```sh
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```<!---sh-->
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make all
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```
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## To use:
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```sh
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```<!---sh-->
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./laman <positive number>
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```
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@@ -17,7 +17,7 @@
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The program accepts ONE POSITIVE number. Seeing is believing, so try things
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like:
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```sh
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```<!---sh-->
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./try.sh
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./laman 4
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@@ -33,14 +33,14 @@ This code should run you in circles.
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Some new compilers (in 1984) dislike lines 6 and 10 of the source, so we changed
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them from:
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```c
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```<!---c-->
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;++f)a[ b<<5|c] =d++,b+ =e;for( f=0;f<O
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<<5|c]^ =a[b<<5 |c]^=a[ (k-(b+1 ))<<5|c]
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```
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to:
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```c
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```<!---c-->
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;++f)a[ b<<5|c] =d++,b+= e;for( f=0;f<O
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<<5|c]^= a[b<<5 |c]^=a[ (k-(b+1 ))<<5|c]
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```
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+11
-11
@@ -141,26 +141,26 @@ Location: <a href="../../location.html#ZZ">ZZ</a> - <em>Unknown location</em></l
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<!-- START: this line starts content for HTML phase 21 by: bin/pandoc-wrapper.sh via bin/md2html.sh -->
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<h2 id="to-build">To build:</h2>
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<div class="sourceCode" id="cb1"><pre class="sourceCode sh"><code class="sourceCode bash"><span id="cb1-1"><a href="#cb1-1" aria-hidden="true" tabindex="-1"></a> <span class="fu">make</span> all</span></code></pre></div>
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<pre class="<!---sh-->"><code> make all</code></pre>
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<h2 id="to-use">To use:</h2>
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<div class="sourceCode" id="cb2"><pre class="sourceCode sh"><code class="sourceCode bash"><span id="cb2-1"><a href="#cb2-1" aria-hidden="true" tabindex="-1"></a> <span class="ex">./laman</span> <span class="op"><</span>positive number<span class="op">></span></span></code></pre></div>
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<pre class="<!---sh-->"><code> ./laman <positive number></code></pre>
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<h2 id="try">Try:</h2>
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<p>The program accepts ONE POSITIVE number. Seeing is believing, so try things
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like:</p>
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<div class="sourceCode" id="cb3"><pre class="sourceCode sh"><code class="sourceCode bash"><span id="cb3-1"><a href="#cb3-1" aria-hidden="true" tabindex="-1"></a> <span class="ex">./try.sh</span></span>
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<span id="cb3-2"><a href="#cb3-2" aria-hidden="true" tabindex="-1"></a></span>
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<span id="cb3-3"><a href="#cb3-3" aria-hidden="true" tabindex="-1"></a> <span class="ex">./laman</span> 4</span>
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<span id="cb3-4"><a href="#cb3-4" aria-hidden="true" tabindex="-1"></a> <span class="ex">./laman</span> 9</span>
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<span id="cb3-5"><a href="#cb3-5" aria-hidden="true" tabindex="-1"></a> <span class="ex">./laman</span> 16</span></code></pre></div>
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<pre class="<!---sh-->"><code> ./try.sh
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./laman 4
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./laman 9
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./laman 16</code></pre>
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<p>This code should run you in circles.</p>
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<h2 id="judges-remarks">Judges’ remarks:</h2>
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<p>Some new compilers (in 1984) dislike lines 6 and 10 of the source, so we changed
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them from:</p>
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<div class="sourceCode" id="cb4"><pre class="sourceCode c"><code class="sourceCode c"><span id="cb4-1"><a href="#cb4-1" aria-hidden="true" tabindex="-1"></a> <span class="op">;++</span>f<span class="op">)</span>a<span class="op">[</span> b<span class="op"><<</span><span class="dv">5</span><span class="op">|</span>c<span class="op">]</span> <span class="op">=</span>d<span class="op">++,</span>b<span class="op">+</span> <span class="op">=</span>e<span class="op">;</span><span class="cf">for</span><span class="op">(</span> f<span class="op">=</span><span class="dv">0</span><span class="op">;</span>f<span class="op"><</span>O</span>
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<span id="cb4-2"><a href="#cb4-2" aria-hidden="true" tabindex="-1"></a> <span class="op"><<</span><span class="dv">5</span><span class="op">|</span>c<span class="op">]^</span> <span class="op">=</span>a<span class="op">[</span>b<span class="op"><<</span><span class="dv">5</span> <span class="op">|</span>c<span class="op">]^=</span>a<span class="op">[</span> <span class="op">(</span>k<span class="op">-(</span>b<span class="op">+</span><span class="dv">1</span> <span class="op">))<<</span><span class="dv">5</span><span class="op">|</span>c<span class="op">]</span></span></code></pre></div>
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<pre class="<!---c-->"><code> ;++f)a[ b<<5|c] =d++,b+ =e;for( f=0;f<O
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<<5|c]^ =a[b<<5 |c]^=a[ (k-(b+1 ))<<5|c]</code></pre>
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<p>to:</p>
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<div class="sourceCode" id="cb5"><pre class="sourceCode c"><code class="sourceCode c"><span id="cb5-1"><a href="#cb5-1" aria-hidden="true" tabindex="-1"></a> <span class="op">;++</span>f<span class="op">)</span>a<span class="op">[</span> b<span class="op"><<</span><span class="dv">5</span><span class="op">|</span>c<span class="op">]</span> <span class="op">=</span>d<span class="op">++,</span>b<span class="op">+=</span> e<span class="op">;</span><span class="cf">for</span><span class="op">(</span> f<span class="op">=</span><span class="dv">0</span><span class="op">;</span>f<span class="op"><</span>O</span>
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<span id="cb5-2"><a href="#cb5-2" aria-hidden="true" tabindex="-1"></a> <span class="op"><<</span><span class="dv">5</span><span class="op">|</span>c<span class="op">]^=</span> a<span class="op">[</span>b<span class="op"><<</span><span class="dv">5</span> <span class="op">|</span>c<span class="op">]^=</span>a<span class="op">[</span> <span class="op">(</span>k<span class="op">-(</span>b<span class="op">+</span><span class="dv">1</span> <span class="op">))<<</span><span class="dv">5</span><span class="op">|</span>c<span class="op">]</span></span></code></pre></div>
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<pre class="<!---c-->"><code> ;++f)a[ b<<5|c] =d++,b+= e;for( f=0;f<O
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<<5|c]^= a[b<<5 |c]^=a[ (k-(b+1 ))<<5|c]</code></pre>
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<p>I hope you have a C beautifier!</p>
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<h2 id="authors-remarks">Author’s remarks:</h2>
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<p>No remarks were provided by the author.</p>
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