Move 1988-2004 entries into subdirs
We we move 1988-2004 entries from all of a year's winning entries in a single directory to each winner being in their own sub-directory under the given year directory.
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char*_,*O;main(S,l)char**l;{*(O=*(l+++S-1)-1)=13,*l[1]=0;for(;;)for(printf(*l),_=O-1;_>=*l&&++*_>(S+*O+S)*S;*_--=(S+*O)*S);}
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Best One Liner:
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Mark Plummer
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2901 Reckord Road
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Fallston, MD, 21047
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USA
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Judges' comments:
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To run:
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make plummer
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./plummer number arg
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where:
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number a number (try 21701)
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arg any argument
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For extra credit: What happens when 'number' contains non-numeric
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characters, and why?
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Selected notes from the author:
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This program prints out all numbers up to a given number of digits
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on a single line. When the largest number is reached, the program
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starts again with 0. It takes two arguments: the first argument
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specifies the number to start counting from and uses leading 0's to
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indicate the number of digits, the second argument can be anything
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but must be present.
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Variable names are single characters chosen for their similarity to
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other characters (O for 0, l for 1, S for 5 (in some fonts), and _
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for ... well nothing really, but it is easy to miss). To prevent
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the need for strlen(), the fact that argv is laid out sequentially
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is exploited (ie. argv[i + 1] == argv[i] + strlen(argv[i]) + 1).
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This is not portable (by the books), but it seems to work
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everywhere I try (actually, for vms, that only holds for i > 1).
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Also, I depend on the fact that a carriage return causes the line
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just written to be overwritten. lint (and most compilers) complain
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that there is no control path leading to a return from main(). At
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125 characters, it still fits on a single line (for those of us who
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don't mind ruining our eyes with 132 column screens).
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The first statement points the base of l (the argument vector) to
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be the first argument by incrementing it. It then assigns O to
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point to the character before the first character of the second
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argument which also happens to be the null termination of the first
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argument. *O gets a \r assigned to it. Finally 0 is assigned to
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the first character of the second argument which has the effect of
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null terminating the first argument after the carriage return had
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removed its null termination. I really tried to make the last part
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of that statement part of the original expression, but the best I
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could do was attach it with a comma (against the advice of K&R).
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The for loop runs the next for loop continuously (actually until
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the machine crashes or the user gets tired of seeing the
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counting). The next for loop is the meat of the program. In the
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initialization statement, the string pointed to by l (the first
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argument containing the digits used for counting followed by a \r)
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is printed, and _ is started at the least significant digit in the
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string. In the test portion, _ is insured not to be past the
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beginning of the string (the most significant digit), and the digit
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pointed to by _ is incremented and checked to be sure that it _is_
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greater than '9' (written here as (S+*O+S)*S). If the test fails,
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either the string has been incremented or each digit in the string
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has been reset to '0'. If the test succeeded, the iteration
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statement assigns '0' (written here as (S+*O)*S (which has the
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added bonus of having the code be a cry for help)) to *_ and
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decrements _ to point to the next more significant digit to be
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incremented; it is done only when a carry situation results (*_ has
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been incremented past '9').
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The inspiration for this program came from actual code which dealt
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with scanning for a unique temporary filename by appending a
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successively larger number to the end of a string.
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Copyright (c) 1993, Landon Curt Noll & Larry Bassel.
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All Rights Reserved. Permission for personal, educational or non-profit use is
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granted provided this this copyright and notice are included in its entirety
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and remains unaltered. All other uses must receive prior permission in writing
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from both Landon Curt Noll and Larry Bassel.
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