Under each yyyy/dir there is a file of the form '*.orig.c' containing the original source code, or as close as we can get to the original source code.
61 lines
3.6 KiB
C
61 lines
3.6 KiB
C
d b,x,h;o q[9802],f[9802];void w(d i){fflush(stdout);printf(
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"%c" , ( i>b)?(i%b>0?q[i-b-1]:10):5*(b==i?2:9));if(i<x+b
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- 1 )w(i+1) ; } d p(o*e,d i ) { e +=i;n h = ( - b-1
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) [ e ] % 2 + ( - b
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) [ e ] % 2 +
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(-b+1)[ e ] % 2 +( - 1 ) [ e
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] % 2+ e [1 ]% 2 +b [ e - 1]% 2 + b[ e ]% 2 +
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b [ e+1 ] %2 ;}d m ( d i ){ n
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( i == x - 1 ) ?0 :( f [ i +
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1 ]=m (i + 1) ) ,32 +3 / (
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( p( q , i )> 3 || h < 2 )? 7 :
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( ( h == 2 &&q[ i ] == 32
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)? 8 : 1 ) );}d y
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( d i ){ d j , s , t ,a ,u
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;if ( x - 1== i ) n 1 ;if ( f [i]==2) {
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f [i ] <<=4;if(y( i))n 1;f[i ]-=- 3 ; if (
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y(i ) )n 1;n 0 ; };if((i % b ) ==
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0 ||( i % b ) == b-
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1 ) n y (i+1 ) ;j
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= -1 ; l : ; j =j + 1 ;
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if ( j >= ( i - i / b + 2
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== b ? 1 : i > 2 * b ?i% b!=
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1 ?2 : 2 * 1<< 1 :8 )) goto
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c; u = p( f, i ) ; if ( i <
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x - 2*b - 1 ) { a =( s =(( t=i % b==
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1) ? 1 : i % b != b
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- 2 ) ) && i < 2 * b;u+= (
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a ? ( j& 4 )
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>> 2 : 0 ) + (t ? ( j & 2 ) / 2 : 0) + (
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s? ( j&1):0);}else a =t=s=0;if((u&2)+(u&4)!= 2 &&
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(q[ i]& 2 ) ==2||u==2&& (f[i]+q[i]) % 2 ==1 ||u
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== 3 && ( q [ i]&2)== 0 )
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goto l ; b
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[i + f ] ^= ! t ? 0
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: b[ i + f ] ^ ( 10 + ( j & 2 )
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/ 2 ) * 3+2;b[ i + f + 1 - b ] ^= !
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a ?0 : b [i + f +1 - b]^ (10+ (
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j & 4) / 4 )* 3 +2 ; b [ i
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+f + 1 ] ^= ! s ?0 : b [i+ f + 1
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] ^ (10 + ( j &1) ) *3+ 2 ; if ( y ( i
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+ 1) ){ n 1 ; }; ( a ?
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i + 1 : 0 ) [ f ] =( t
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? i+ b :0
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) [ f ] = ( s ? i
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+ b +1:0) [ f ] = 2 ;goto l ; c:n 0 ; } d
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main(d c,o**v){d i; x=b=0;while((q[x++]=getchar() ) !=
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EOF ){x-=(q[x-1]==10)? b+=1,1:0;q[x-1]^= (q[x-1] ==
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32)? 0 : q [ x - 1 ] ^ 35 ; } ; w ( 0 );
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for ( ; ;
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) { z ( f , 2 , x *
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k ( o ) ) ; for ( i = 0;i<=x - 1;
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i = i + b )q [ i / b] = q [ x - b+ i /b
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] = q [ i ]= q [ i - (
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(i == 0) ? 0: 1) ] =f [ i /
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b ] = f[ x -b -1+ i/ b] = f [i ] =f[
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i - ( ( i == 0 ) ?
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0 :1 ) ] = 32; if ( c ==
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1 ) m ( 0 ); else
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if (y ( b + 1)
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==0)n 1;f[0]<<=1<<2;memcpy(q,f,x*k(o));w(0);sleep(1);};n 0;}
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