Cody Boone Ferguson
3141392cc1
The author stated that the program assumes EOF is -1 but for systems that do not have this it will fail. This is indeed a valid concern as the standard mandates that it's a value < 0 but it doesn't require it to be -1. The author also stated that the program could fail if 1 is not a return value that indicates error so this was changed to EXIT_FAILURE as the suggested was made. It is possible of course that I missed a place where this should have been updated but I don't believe so. I am unaware of any system where this would be a problem and I don't know why it matters anyway but I made the change as the author stated it could be a problem with portability. The README.md file has been formatted and typo checked. Added try.sh script. This should complete this entry's review.
22 lines
1.1 KiB
C
22 lines
1.1 KiB
C
#include <stdio.h>
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#include <stdlib.h>
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#define exit(a) return EXIT_FAILURE
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int main(int a,char **A){FILE*B;typedef unsigned long C;C b
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[8]; if(!(a==7&&(B= fopen(1[A],"rb")))) exit(1); for(7[b]=0
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;7[b]<5;7[b]++)b[7[ b]]=strtoul(A[2+7[b ]],0,16-!7[b]*6);5[
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b]=3[b] ; while ((6[b]= getc(B)
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) !=EOF ){if(2 [b])for (7[b]=0
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;7[b]<4 ;7[b]++ )if(((6 [b]>>7[
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b])^(6[ b]>>(7-7[b])))&1)6[ b] ^=(1
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<<7[b]) ^(1<<(7-7[b]));5[b] ^= 6[b]
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<<(0[b] -8);for(7[b]=0;7[b] <8;7[b]
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++)if(( 5[b]>>(0[b]- 1))&1)5
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[b]=(5[ b]<<1)^ 1[b]; else 5[
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b]<<=1; }5[b]&=((((C)1 <<(0[b]
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-1))-1) <<1)|1; if(2[b] )for(7[
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b]=0;7[ b]<(0[b ]>>1);7 [b] ++)
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if(((5[b]>>7[b])^(5 [b]>>(0 [b]-1-7 [b])))&1)5[b]^=((C)
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1<<7[b])^((C)1<<(0[ b]-1-7[ b]));5[ b]^=4[b];fclose(B);
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printf("%0*lX\n", ( int)(0[ b]+3)>> 2,5[b]); return 0;}
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