Landon Curt Noll
2ba12ecc3c
Under each yyyy/dir there is a file of the form '*.orig.c' containing the original source code, or as close as we can get to the original source code.
91 lines
3.8 KiB
C
91 lines
3.8 KiB
C
#include <stdio.h>
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char E[1<<25]=" ; } } { { } { { ; ; { } } { { ; { { { { { } ; } { { ; { { { ; { } ; ; ; { ; ; ; } } ; } { { ; } } ; } } ; ; } { ; } } { } } } } } ; { { } } } ; } } } { } ; ; ; { } ; { { { ; { ; } } { { { } { { ; ; { { } } { { ; { { { { { } ; } { { ; { { { ; { } ; ; ; ; ; } } ; } { { ; } } ; } ; ; } { ; } } } } } } } ; { { } ; ; } ; { } ; ; ; { } ; { { ; { ; } } { { { } { ; ; { { } } { { { { { { { { ; { ; { { ; { { ; ; { } ; ",
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*a[40],*q=E+20,*T=E+1080;
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int i=1,j,k,l,u,w,I,J,K,h,H,G,R=4,U,e[999],*p=e+5,*r,*s,*v,b[999],L[1<<16],
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F=882,n[99];
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FILE*f;
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#define Y(a,b) (a)<(b)?(a):(b)
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#define Z(a,b) (a)>(b)?(a):(b)
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#define X(x,a,b)Z(a,Y(b,x))
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#define O [s]
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#define N [v]
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#define M [r]
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#define C ++
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#define m :0
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#define g m,
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#define d u==
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#define z(o) 32 O?n[X(32 O+o+(35 O-24)/256,0,59)]m
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#define y(o) 32 O?8 O=z(o)m
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#define x (p=e+5*34 O,2 M-3 && 2 M-5?y(0),l=p[4],a[i]=a[8+34 O],3 N=l>1?\
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2*(p[3]+l):2*p[0],4 N=l>1?2*l:1,0 N=Y(2 M-9?0:9 O<<8,3 N-1) m)
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#define W(t,i) (u=t[i]>>4,w=t[i]&15),
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#define Q(e) ((1 N+=13200)>=5 N?1 N-=5 N, C 0 N>=3 N?0 N-=4 N m g e*6 N*q[0\
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N]/34)+
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#define D(b,i) T[i]==*#b&&T[i+2]==#b[1]
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#define A ((unsigned char*)q)
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#define V *p C=
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#define S(a) V(A[a]<<8)|A[a+1],
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#define P 2 M==
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#define B ,putchar
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#define o for(
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int main(int t,char**c)
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{
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o; w=E[u]; C u)n[u/10]+=(w-59?w-125?w-32?1 m:2:3)<<u%10;
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o t=fread(E,i,1<<24,f=fopen(c[i],"rb")),
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t=D(FT,0)?R=T[3]-48,32:D(CN,1)?R=*T-48,32:D(MK,0)?32:16;
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i C<t;
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S(0)V(A[2]&7)-2*(A[2]&8),V A[3],S(4)S(6)q+=8) q+=22;
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o H=*A,T=q+=2,q+=t>15?132:128;
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k<128;
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k C) G=X(G,T[k]+1,128);
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o p=L; j C<R*64*G; q+=4)
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o W(A,2)V*A&240|u,V i=0,V w,V A[3],k=((*A&15)<<8)|A[1],l=9<<19;
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k&&i C<60;
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u=k-n[i],u*u<l?p[-3]=i,l=u*u:l);
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o i=1; i<t; a[8+i]=q,q+=2*e[5*i C]);
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o t=6; !U; ) {
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o i=0; i<R;
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v=b+7*i,r=L+4*(R*(64*T[K]+J)+i),s=e+200+50*i,j=3 M&15,
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I?
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W(s,2 M)P 5||P 6||P 10?0 O =u?Y(0 O+u,64):Z(0 O-w,0) g
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P 0?W(r,3)(u|w)?y((I%3-1?I%3-2?0:w:u)) m g
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8 O=P 1?Z(113,8 O-1 O):P 2?Y(856,8 O+2 O):8 O,
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P 5||P 3?l=z(0),8 O>l?8 O=Z(8 O-3 O,l):8 O<l?Y(8 O+3 O,l) m g
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U|=P 11&&I==t-1,
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P 13&&I==t-1?W(r,3)K C,J=10*u+w-1 g
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P 14?
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W(r,3)
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d 6?j?I==t-1?38 O=38 O<j?J=37 O-1,38 O+1 m m:(37 O=J) g
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d 9&&C 39 O==25 O?39 O=0,x g
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d 12&&I==28 O?0 O=0 g
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d 13&&I==e[29]?x m
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m
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:(
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0 M?34 O=0 M,p=e+5*34 O,35 O=p[1],0 O=p[2] g
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3 M?2 M O=3 M g
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1 M&&(2 M-14||((3 M>>4)-13))?32 O=1 M,x g
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0 O=P 12?X(3 M,0,64) m O ,
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P 15?(l=3 M)?l<33?t=l:(F=110250/l) m g
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P 14?
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W(r,3)
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j?(16+u) O=j g
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8 O=d 1?Z(113,8 O-17 O):d 2?Y(856,8 O+18 O):8 O,
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d 5?35 O=(j&7)-2*(j&8) g
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d 9?39 O=25 O&&!1 M?x,0 m g
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0 O=d 10?Y(0 O+26 O,64):d 11?Z(0 O-27 O,0):0 O,
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d 14?h=30 O m m),
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6 N =X(0 O,0,64),
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5 N =999*8 O,
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i C);
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o C I>=t+t*h?I=h=0,C J>=64?J=0,U|=C K>=H m g j=F; j--; 0
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B(u)B(u>>8)B(w)B(w>>8))
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o i=u=w=0; i<R;
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v=b+7*i,q=a[i C],q?l=Q(1)Q(4)Q(12)Q(12)Q(4)Q(1)0,
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k=1<<(i&2),u+=l/k,w+=l/(k^5) m);
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}
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return 0;
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}
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