refactor: Simplify SpanPopBack

Use the equivalent back() and first() member functions.
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MarcoFalke committed 2024-12-19 13:46:52 +01:00
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commit faae6fa5f6
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@@ -248,9 +248,8 @@ template <typename T>
T& SpanPopBack(Span<T>& span)
{
size_t size = span.size();
ASSERT_IF_DEBUG(size > 0);
T& back = span[size - 1];
span = Span<T>(span.data(), size - 1);
T& back = span.back();
span = span.first(size - 1);
return back;
}