set pandoc 8 character tab stops for HTML conversion

We add `--tab-stop=8` to all `pandoc(1)` executions in order to set
a better tab stop indentation, especially for tab intended code blocks.

Changed `bin/pandoc-wrapper.sh` VERSION "1.5.3 2024-03-26"
to "1.6 2024-03-31".

Fixed `1991/brnstnd/sorta.README.md` so that the sorta code
is code blocks.

Removed unneeded paragraph group in copyright in `inc/footer.default.html`.

Performed `make www` to perform the above and test under macOS.
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@@ -218,44 +218,44 @@ since it is equivalent to <code>S K K</code>:</p>
<p>The algorithm for translating lambda expressions into combinator
expressions works as follows. There are three forms of lambda expression
to consider: variables, applications, and abstractions.</p>
<pre><code>trans v -&gt; v (variable)
trans a b -&gt; (trans a) (trans b ) (application)
trans \ab -&gt; abs a (trans b) (abstraction)</code></pre>
<pre><code>trans v -&gt; v (variable)
trans a b -&gt; (trans a) (trans b ) (application)
trans \ab -&gt; abs a (trans b) (abstraction)</code></pre>
<p>There are a further three cases to consider for the body of lambda
expressions, where we need to do the magic that transforms away the
variables.</p>
<pre><code>abs a f x -&gt; S (abs a f) (abs a x)
abs a b -&gt; K b (b != a)
abs a a -&gt; I</code></pre>
<pre><code>abs a f x -&gt; S (abs a f) (abs a x)
abs a b -&gt; K b (b != a)
abs a a -&gt; I</code></pre>
<p>E.g. suppose we had combinator expressions for <code>+</code> and <code>3</code> and we wanted
to see what the combinator expression for doubling 3 looked like:</p>
<pre><code> trans \x(+ x x) 3
-&gt; (trans \x(+ x x)) (trans 3)
-&gt; (abs x (trans + x x)) 3
-&gt; (abs x + x x) 3
-&gt; S (abs x + x) (abs x x) 3
-&gt; S (S (abs x +) (abs x x)) I 3
-&gt; S (S (K +) I) I 3
-&gt; S (S (K +) I) I 3</code></pre>
-&gt; (trans \x(+ x x)) (trans 3)
-&gt; (abs x (trans + x x)) 3
-&gt; (abs x + x x) 3
-&gt; S (abs x + x) (abs x x) 3
-&gt; S (S (abs x +) (abs x x)) I 3
-&gt; S (S (K +) I) I 3
-&gt; S (S (K +) I) I 3</code></pre>
<p>We can then check that this evaluates to the expected result:</p>
<pre><code> S (S (K +) I) I 3
-&gt; S (K +) I 3 (I 3)
-&gt; K + 3 (I 3) (I 3)
-&gt; + (I 3) (I 3)
-&gt; + 3 3</code></pre>
-&gt; S (K +) I 3 (I 3)
-&gt; K + 3 (I 3) (I 3)
-&gt; + (I 3) (I 3)
-&gt; + 3 3</code></pre>
<p>It is possible to perform a slightly more compact translation with a
couple of simple optimisations. For example, note that <code>K (a b)</code> is the
same as <code>S (K a) (K b)</code>, because</p>
<pre><code> K (a b) x
-&gt; a b</code></pre>
-&gt; a b</code></pre>
<p>and</p>
<pre><code> S (K a) (K b) x
-&gt; K a x (K b x)
-&gt; a b</code></pre>
-&gt; K a x (K b x)
-&gt; a b</code></pre>
<p>Also, <code>S (K a) I</code> is the same as just <code>a</code> because</p>
<pre><code> S (K a) I x
-&gt; K a x (I x)
-&gt; a x</code></pre>
-&gt; K a x (I x)
-&gt; a x</code></pre>
<p>The program simply reads a lambda expression from the standard input,
translates it into a combinator expression using the transformation and
optimisations described above, and prints out the result.</p>
@@ -430,11 +430,11 @@ International Logic Programming Symposium, 1995.</p>
You are free to share and adapt this file under the terms of this license:
Creative Commons Attribution-ShareAlike 4.0 International (CC BY-SA 4.0)
Creative Commons Attribution-ShareAlike 4.0 International (CC BY-SA 4.0)
For more information, see:
https://creativecommons.org/licenses/by-sa/4.0/
https://creativecommons.org/licenses/by-sa/4.0/
-->
@@ -498,7 +498,7 @@ International Logic Programming Symposium, 1995.</p>
<div class="footer">
<h2>Copyright and CC BY-SA 4.0 License</h2>
<p>This file and web page is:</p>
<blockquote><p><b>Copyright &copy; 1984-2024 by Landon Curt Noll. All Rights Reserved.</b></p></blockquote>
<blockquote><b>Copyright &copy; 1984-2024 by Landon Curt Noll. All Rights Reserved.</b></blockquote>
<p>You are free to share and adapt this file under the terms of this license:</p>
<blockquote><b>Creative Commons Attribution-ShareAlike 4.0 International (CC BY-SA 4.0)</b></blockquote>
<p>For more information, see:</p>