Merge pull request #410 from xexyl/1995-cdua
Move usleep() version of 1995/cdua to cdua.alt.c
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@@ -1 +1,2 @@
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cdua
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cdua.alt
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+7
-3
@@ -61,7 +61,7 @@ CDEFINE= -DZ=3000
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# Include files that are needed to compile
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#
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CINCLUDE=
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CINCLUDE= -include stdio.h -include stdlib.h
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# Optimization
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#
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@@ -112,8 +112,8 @@ OBJ= ${PROG}.o
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DATA=
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TARGET= ${PROG}
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#
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ALT_OBJ=
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ALT_TARGET=
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ALT_OBJ= ${PROG}.alt.o
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ALT_TARGET= ${PROG}.alt
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#################
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@@ -135,6 +135,10 @@ ${PROG}: ${PROG}.c
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alt: data ${ALT_TARGET}
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@${TRUE}
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${ALT_TARGET}: ${PROG}.alt.c
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${CC} ${CFLAGS} $< -o $@ ${LIBS}
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# data files
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#
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data: ${DATA}
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+43
-8
@@ -18,13 +18,13 @@ would work with macOS. Once it could compile it additionally segfaulted under
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macOS which he also fixed. Thank you Cody for your assistance!
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NOTE: on modern systems this was hard to see it solve it in real time because it
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goes so quickly so Cody added a macro `Z` defaulting to 3000 for a call to
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`usleep()` to make it easier to see. The `Z` macro lets you configure it in case
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you find it too slow or too fast. To do that:
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goes so quickly so Cody added an alternate version which makes it easier with
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modern systems to see the maze actually being solved in real time. We encourage
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you to use this version but we keep the original here to both preserve the
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original code (the bug fixes notwithstanding) and it will also let you see just
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how fast your computer is :-) (and you can also use both to see the difference).
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For this alternate, slower version, please see below.
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```sh
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make CFLAGS+="-DZ=1500" clobber all
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```
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## To run:
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@@ -37,11 +37,46 @@ NOTE: sometimes the program needs you to press enter a second time to continue
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solving the maze. See [bugs.md](/bugs.md) for more details.
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## Judges' remarks
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### Alternate code:
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This version uses `usleep(3)` with the `Z` (defined in the Makefile, default
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`3000`) microseconds to make it easier to see the maze being solved in real
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time. You can redefine Z to reconfigure it in case it's going too slow, too
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fast :-) or you're doing some strange experiment like making it 100000 (which
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Cody did for fun :-) ). To compile and use without reconfiguring the 3000
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microseconds, try:
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```sh
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make clobber alt
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./cdua.alt # press enter
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```
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Use `cdua.alt` as you would `cdua` above.
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To use a 1500 for `Z` try something like:
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```sh
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make CFLAGS="-DZ=1500" clobber alt
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./cdua.alt # press enter and watch it move a bit slower
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```
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Also try:
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```sh
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make CFLAGS="-DZ=65000" clobber alt
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./cdua.alt # press enter and watch it go much slower!
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```
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Do you see anything strange in this version when `Z` is a high value like
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`65000`? What happens if you use `100000`? Is this strange output still there?
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Why?
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## Judges' remarks:
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This could be used as the basis of an a-maze-ing screen exerciser.
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## Author's remarks
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## Author's remarks:
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A program that generates a maze, and then solves it, all this being
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seen by the user. Some highlights of obfuscation are: 3 steps
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@@ -0,0 +1,20 @@
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#include <stdlib.h>
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#include <stdio.h>
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#include <unistd.h>
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#define r return
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char*u0="<RET> to begin... ",*u1="Already been here!",*u2="Found a wall! \
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",*u3="Walking... ",*u4="Finished. ",*u5="Going back..\
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. ",*o="\033[23;1HDone!!\n",*x="\033[2J",*y="\033[1;1H",*z="\033[%d;%\
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dH%c",*w="\033[1;1H%s",*v="\033[%d;%dH%c\033[%d;%dH%c\033[%d;%dH%c",b[1841
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];int c,d,e,f,g;typedef int(*h)();h i,k,l,m,n;rand(
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),time(),getchar();int main(int a){k=rand,l=time,m=getchar,
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n=main;if(!c)for(srand(l(0)),g=a=1000,--d;++d<1840;b[c=d]=" #\n"[d%80==79?2:d/80
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&&d%80&&d/80-22&&d%80-78]);if(!(c-1839))++c,printf("%s%s%s",x,y,b);k:if(!(c-1840)
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&&(b[a+2]+b[a-2]+b[a+160]+b[a-160]-4*' ')){while(b[a+(f=(e=k()%4)?e-1?e-2?-1
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:1:-80:80)*2]!='#');b[a]=b[a+f]=b[f+a+f]=' ';printf(v,a/80+1,1+a%80,' ',(a+f)/80+
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1,1+(a+f)%80,' ',(f+a+f)/80+1,1+(f+a+f)%80,' ');n(f+a+f);goto k;}else if(!(g
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-a))c=1,a=162,printf(w,u0),m();if(c-1){}else r b[a]!=' '?(usleep(Z),printf(w,b[a]=='.'?u1:u2),0)
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:(b[a]='.',printf(w,u3),printf(z,a/80+1,1+a%80,'.'),a==1676?(printf(w,u4),printf(o),1):n(a+1)||n
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(a+80)||n(a-80)||n(a-1)?1:(b[a]=' ',printf(w,u5),printf(z,a/80+1,1+a%80,' '),0));r 0;}
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+1
-5
@@ -1,7 +1,3 @@
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#include <stdlib.h>
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#include <stdio.h>
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#include <unistd.h>
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#define r return
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char*u0="<RET> to begin... ",*u1="Already been here!",*u2="Found a wall! \
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@@ -15,6 +11,6 @@ n=main;if(!c)for(srand(l(0)),g=a=1000,--d;++d<1840;b[c=d]=" #\n"[d%80==79?2:d/80
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&&(b[a+2]+b[a-2]+b[a+160]+b[a-160]-4*' ')){while(b[a+(f=(e=k()%4)?e-1?e-2?-1
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:1:-80:80)*2]!='#');b[a]=b[a+f]=b[f+a+f]=' ';printf(v,a/80+1,1+a%80,' ',(a+f)/80+
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1,1+(a+f)%80,' ',(f+a+f)/80+1,1+(f+a+f)%80,' ');n(f+a+f);goto k;}else if(!(g
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-a))c=1,a=162,printf(w,u0),m();if(c-1){}else r b[a]!=' '?(usleep(Z),printf(w,b[a]=='.'?u1:u2),0)
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-a))c=1,a=162,printf(w,u0),m();if(c-1){}else r b[a]!=' '?(printf(w,b[a]=='.'?u1:u2),0)
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:(b[a]='.',printf(w,u3),printf(z,a/80+1,1+a%80,'.'),a==1676?(printf(w,u4),printf(o),1):n(a+1)||n
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(a+80)||n(a-80)||n(a-1)?1:(b[a]=' ',printf(w,u5),printf(z,a/80+1,1+a%80,' '),0));r 0;}
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